32x^2=15,49

Solution for 32x^2=15,49 equation:

32x^2=15.49

We move all terms to the left:

32x^2-(15.49)=0

We add all the numbers together, and all the variables

32x^2-15.49=0

a = 32; b = 0; c = -15.49;
Δ = b2-4ac
Δ = 02-4·32·(-15.49)
Δ = 1982.72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1982.72}}{2*32}=\frac{0-\sqrt{1982.72}}{64}
=-\frac{\sqrt{}}{64}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1982.72}}{2*32}=\frac{0+\sqrt{1982.72}}{64}
=\frac{\sqrt{}}{64}
$